2r^2+6r-56=0

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Solution for 2r^2+6r-56=0 equation: 



2r^2+6r-56=0

a = 2; b = 6; c = -56;
Δ = b2-4ac
Δ = 62-4·2·(-56)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$


$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-22}{2*2}=\frac{-28}{4}
=-7
$


$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+22}{2*2}=\frac{16}{4}
=4
$

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